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An electron enters the region between the plates of a parallel-plate capacitor with some initial velocity at an angle $θ$ to the plates. The plate width is $l$ and the plate separation is d. The electron follows the path shown, just missing the upper plate. Neglect gravity,then

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$\tan θ = \frac{2 d}{l}$

$\tan θ = \frac{4 d}{l}$

$\tan θ = \frac{6 d}{l}$

$\tan θ = \frac{8 d}{l}$

answer is B.

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Detailed Solution

$d = \frac{u^{2} \sin^{2} θ}{2 g} a n d l = \frac{2 u^{2} \sin θ \cos θ}{g}$

$\Rightarrow \frac{d}{l} = \frac{\tan θ}{4} \Rightarrow \tan θ = \frac{4 d}{l}$

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