An electron has velocity  $\overline{\text{V}}=(2\times {10}^6\text{m/s)}\widehat{i}+(3\times {10}^6\text{m/s})\widehat{j}$Magnetic field present in the region is $\overline{B}=0.03\text{T}\widehat{i}-0.15\text{T}\widehat{j}$.The force on the electron is 

$$\begin{gathered} \overline{v}=\left(2\times {10}^6\widehat{i}+3\times {10}^6\widehat{j}\right)\text{m/s} \\ \overline{B}=\left(0.03\widehat{i}-0.15\widehat{j}\right)\text{T} \\ \text{q}=-{\text{1.6×10}}^{-19}\text{C} \\ \overline{F}=? \\ \overline{F}=\text{q}\left(\overline{v}\times \overline{B}\right) \\ \overline{F}=-1.6\times {10}^{-19}\left|\begin{array}{ccc}\widehat{i}& \widehat{j}& \widehat{k}\\ 2\times {10}^6& 3\times {10}^6& 0\\ 0.03& -0.15& 0\end{array}\right| \\ =-1.6\times {10}^{-19}\left[2\times {10}^6\left(-0.15\right)-3\times {10}^6\times 0.03\right]\widehat{k} \\ =\left(0.48+0.144\right)\widehat{k}\times {10}^{-13} \\ =0.624\times {10}^{-13}\widehat{k} \\ =\left(6.24\times {10}^{-14}\right)\widehat{k} \end{gathered}$$