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An electron in a hydrogen atom in its ground state absorbs1.5 times as much energy as the minimum required for it to escape from the atom. The velocity of the emitted electron in the scientific notation is $x \times 10^{y} m / s$ . Then the value of y is

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answer is 6.

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Detailed Solution

Energy absorbed $= 13.6 \times 1.5 = 20.4 e V$ .
Of this 6.8eV is converted to K.E. as I.E. is 13.6 eV
$K . E = \frac{1}{2} m v^{2} = 6.8 \times 1.6 \times 10^{19} J .$
$v = 1.54 \times 10^{6} m / s$

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