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Q.

An electron in a hydrogen atom undergoes a transition from an orbit with quantum number ni to another with quantum number nf .Vi and Vf are respectively the initial and final potential energies of the electrons. If ViVf=6.25, then the smallest possible nf is

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answer is 5.

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Detailed Solution

Potential energy =27.2n2ineV
Vi=27.2ni2 and Vf=27.2nf2
ViVf=nf2ni2=6.25 (given)
nfni=2.5 
for ni=2
nf=5(smallest possible value)
 

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