An electron in ground state of hydrogen has an angular momentum L1 and an electron in the first excited state of Lithium has an angular momentum L2. Then L2

L=nh2π;∴L1=1h2π and L2=2h2πL1L2=2;∴L1=L22

An electron in ground state of hydrogen has an angular momentum L1 and an electron in the first excited state of Lithium has an angular momentum L2. Then L2

L=nh2π;∴L1=1h2π and L2=2h2πL1L2=2;∴L1=L22

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An electron in ground state of hydrogen has an angular momentum L₁ and an electron in the first excited state of Lithium has an angular momentum L₂. Then L₂

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L₁= L₂

L₁= 2L₂

L₁= 4L₁

L₁= L₂/2

answer is C.

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$\begin{array}{l} L = \frac{nh}{2 π}; ∴ L_{1} = \frac{1 h}{2 π} and L_{2} = \frac{2 h}{2 π} \\ \frac{L_{1}}{L_{2}} = 2; ∴ L_{1} = \frac{L_{2}}{2} \end{array}$

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An electron in ground state of hydrogen has an angular momentum L1 and an electron in the first excited state of Lithium has an angular momentum L2. Then L2

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An electron in ground state of hydrogen has an angular momentum L₁ and an electron in the first excited state of Lithium has an angular momentum L₂. Then L₂