An Electron is constrained to move along the y-axis with a speed of 0.1 c( c is the speed of light ) in the presence of electronic wave , whose electric field E→=30 sin(1.5×107t-5×10-2x)V/m. The maximum magnetic force experienced by the electron will be :( Given C = 3×108 ms-1 and electron charge =1.6×10-19C )

Bmax=EmaxC=303×108=10−7TFmax=qvB⇒Fmax=1.6×10−19×0.1×3×108×10−7=4.8×10−19N

An Electron is constrained to move along the y-axis with a speed of 0.1 c( c is the speed of light ) in the presence of electronic wave , whose electric field E→=30 sin(1.5×107t-5×10-2x)V/m. The maximum magnetic force experienced by the electron will be :( Given C = 3×108 ms-1 and electron charge =1.6×10-19C )

Bmax=EmaxC=303×108=10−7TFmax=qvB⇒Fmax=1.6×10−19×0.1×3×108×10−7=4.8×10−19N

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An Electron is constrained to move along the y-axis with a speed of 0.1 c( c is the speed of light ) in the presence of electronic wave , whose electric field $\vec{E} {=30 sin(1.5×10}^{7} {t-5×10}^{-2} x)V/m.$ The maximum magnetic force experienced by the electron will be :
( Given ${C = 3×10}^{8} {ms}^{-1}$ and electron charge ${=1.6×10}^{-19} C$ )

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${4.8×10}^{-19} N$

${3.2×10}^{-18} N$

${2.4×10}^{-18} N$

${1.6×10}^{-19} N$

answer is A.

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Detailed Solution

$\begin{array}{l} B_{max} = \frac{E_{\max}}{C} = \frac{30}{3 \times 10^{8}} = 10^{- 7} T \\ F_{m a x} = q v B \\ \Rightarrow F_{\max} = 1.6 \times 10^{- 19} \times (0.1 \times 3 \times 10^{8}) \times 10^{- 7} = 4.8 \times 10^{- 19} N \end{array}$

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