An electron is moving around a proton in an orbit of radius 1A0 and produces 16 Wb/m2 of magnetic field at the centre, then find the angular velocity of electron

B=μ0qω4πr⇒ω=B×4πrμ0q=16×4π×10−104π×10−7×1.6×10−19=10×1016rad/s

An electron is moving around a proton in an orbit of radius 1A0 and produces 16 Wb/m2 of magnetic field at the centre, then find the angular velocity of electron

B=μ0qω4πr⇒ω=B×4πrμ0q=16×4π×10−104π×10−7×1.6×10−19=10×1016rad/s

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An electron is moving around a proton in an orbit of radius 1A⁰ and produces 16 Wb/m² of magnetic field at the centre, then find the angular velocity of electron

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$20 π \times 10^{16} r a d / \sec$

$10 \times 10^{16} r a d / \sec$

$\frac{5}{2 π} \times 10^{16} r a d / \sec$

$\frac{5}{4 π} \times 10^{16} r a d / \sec$

answer is B.

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Detailed Solution

$B = \frac{μ_{0} q ω}{4 π r}$

$\Rightarrow ω = \frac{B \times 4 π r}{μ_{0} q}$

$= \frac{16 \times 4 π \times 10^{- 10}}{4 π \times 10^{- 7} \times 1.6 \times 10^{- 19}}$

$= 10 \times 10^{16} r a d / s$

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