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Q.

An electron is moving with speed v. Its energy and energy of a photon are equal then $\frac{λ_{e}}{λ_{photon}} = \dots$

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a

$\frac{c^{2}}{2 V}$

b

$\frac{v}{c}$

c

$\frac{v^{2}}{2 c}$

d

$\frac{v}{2 c}$

answer is B.

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Detailed Solution

$λ_{photon} = \frac{h c}{E}$

$λ_{photon} = \frac{hc}{\frac{hv}{2 λ_{e}}} = \frac{(2 C) λ_{e}}{V}$

$\frac{λ_{e}}{λ_{photon}} = \frac{V}{2 C}$

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