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An electron is projected with velocity $v_{0}$ in a uniform electric field E perpendicular to the field. Again it is projected with velocity $v_{0}$ perpendicular to a uniform magnetic field B. If $r_{1}$ is initial raidus of curvature just after entering in the electric field and $r_{2}$ is initial raidus of curvature just after entering in magnetic field then the ratio $r_{1} / r_{2}$ is equal to

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$\frac{B V_{0}^{2}}{E}$

$\frac{B}{E}$

$\frac{E V_{0}}{B}$

$\frac{B V_{0}}{E}$

answer is D.

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Detailed Solution

$r_{1} = \frac{m v^{2}}{q E}; r_{2} = \frac{m v}{q B}$

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