An electron is released from rest in an uniform electric field of 576 N/C. Then,

Acceleration of a charge q, when released from rest in a field of intensity E is

                                 $\mathrm{a}=\frac{\mathrm{F}}{\mathrm{m}}=\frac{\mathrm{qE}}{\mathrm{m}}$

$\begin{array}{c}\therefore \text{ For electron, }\mathrm{a}=\frac{\mathrm{eE}}{\mathrm{m}}=\frac{1.6\times {10}^{-19}\times 576}{9.1\times {10}^{-31}}\\ =1.01\times {10}^{14}\mathrm{m}/{\mathrm{s}}^2\end{array}$

Acceleration is constant.

Also, electron is accelerated opposite to field.