An electron is revolving in a circular path if angular momentum of it is L→ and magnetic moment of the path is M→, then (q is the charge of the electron and m is the mass of the electron)

ML=i×πR2MR2ω=ef×πMω;f=ω2πM→ is the direction of flow of current whereas L→ depends on direction of rotation of electrons.

An electron is revolving in a circular path if angular momentum of it is L→ and magnetic moment of the path is M→, then (q is the charge of the electron and m is the mass of the electron)

ML=i×πR2MR2ω=ef×πMω;f=ω2πM→ is the direction of flow of current whereas L→ depends on direction of rotation of electrons.

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An electron is revolving in a circular path if angular momentum of it is $\vec{L}$ and magnetic moment of the path is $\vec{M}$ , then (q is the charge of the electron and m is the mass of the electron)

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$\vec{L} & \vec{M}$ are in the same direction with $\frac{|M|}{|L|} = \frac{q}{2 m}$

$\vec{L} & \vec{M}$ are in opposite direction with $\frac{|M|}{|L|} = \frac{2 m}{q}$

$\vec{L} & \vec{M}$ are in the same direction with $\frac{|M|}{|L|} = \frac{2 m}{q}$

$\vec{L} & \vec{M}$ are in opposite direction with $\frac{|M|}{|L|} = \frac{q}{2 m}$

answer is D.

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$\frac{M}{L} = \frac{i \times π R^{2}}{M R^{2} ω} = \frac{e f \times π}{M ω}; f = \frac{ω}{2 π}$

$\vec{M}$ is the direction of flow of current whereas $\vec{L}$ depends on direction of rotation of electrons.

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An electron is revolving in a circular path if angular momentum of it is L→ and magnetic moment of the path is M→, then (q is the charge of the electron and m is the mass of the electron)

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An electron is revolving in a circular path if angular momentum of it is $\vec{L}$ and magnetic moment of the path is $\vec{M}$ , then (q is the charge of the electron and m is the mass of the electron)