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Q.

An electron (mass = 9x10^-31 kg, charge = 1.6 x 10^-19 C) moving with a velocity of 10⁶ m/s enters a region where magnetic field exists. If it
describes a circle of radius 0.10m, the intensity of the magnetic field must be

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a

$14.4 \times 10^{- 5} T$

b

$1 \cdot 3 \times 10^{- 6} T$

c

$5 \cdot 6 \times 10^{- 5} T$

d

$1 .8 \times 10^{- 4} T$

answer is B.

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Detailed Solution

$\begin{array}{l} r = \frac{mv}{qB} \\ ∴ 0 \cdot 10 = \frac{(9 \times 10^{- 31}) (10^{6})}{(1 \cdot 6 \times 10^{- 19}) B} \end{array}$
or $B = \frac{(9 \times 10^{- 31}) (10^{6})}{(1 .6 \times 10^{- 19}) (0 \cdot 10)} = 5 \cdot 6 \times 10^{- 5} tesla$

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