Q.

An electron (mass m) with an initial velocity v = v0i^ is in an electric field E = E j^.  If initial wavelength λ0=h/mv0, then its de Broglie wavelength at time t is given by 

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a

λ0

b

λ01+e2E02t2m2v02

c

λ01+e2E02t2m2v02

d

λ01+Etmv0 

answer is C.

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Detailed Solution

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F=eEoj^       a=emEoj^

 V=u+at  =voi^emEotj^

V=vo2+e2Eo2t2m2  λ=hmv

=hmv021+e2E02t2m2v02

=hmvo1+e2E02t2m2v02   =λo1+e2E02t2m2v02

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