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An electron moves straight inside a charged parallel plate capacitor of uniform charge density $σ$ . The space between the plates is filled with uniform magnetic field of intensity B, as shown in the figure. Neglecting effect of gravity, the time of straight line motion of the electron in the capacitor is :

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$\frac{σ}{ε_{0} l B}$

$\frac{ε_{0} B}{σ}$

$\frac{σ}{ε_{0} B}$

$\frac{ε_{0} l B}{σ}$

answer is D.

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Detailed Solution

$q E = q v B, E = \frac{σ}{ε_{0}} \frac{E}{B} = v t = \frac{l}{v} = \frac{l B}{E} = \frac{ε_{0} l B}{σ}$

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