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An electron of charge ‘e’ moves in a circular orbit of radius ‘r’ around the nucleus at a frequency ‘n’. The magnetic moment associated with the orbital motion of the electron is

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$\frac{{πnr}^{2}}{e}$

πner²

$\frac{πne}{r^{2}}$

$\frac{{πer}^{2}}{n}$

answer is A.

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Detailed Solution

M = iA = (en)πr²

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