An electron (of charge e) revolves around a long wire with uniform charge density λ in a circular path of radius r. Its kinetic energy is given by

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An electron (of charge e) revolves around a long wire with uniform charge density $λ$ in a circular path of radius r. Its kinetic energy is given by

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$\frac{λ e}{4 π ε_{0}}$

$\frac{λ e}{2 π ε_{0} r}$

$\frac{λ e}{2 π ε_{0}}$

$\frac{λ e}{4 π ε_{0} r}$

answer is D.

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Detailed Solution

$F = {mv}^{2} / r \Rightarrow (λe / 2 {πε}_{0} r) = {mv}^{2} / r$

$K . E = \frac{1}{2} {mv}^{2} = \frac{λe}{4 {πε}_{0}}$

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