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Q.

An electron of mass m, when accelerated through a potential difference V has de-Broglie wavelength λ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

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a

λmM

b

λMm

c

λmM

d

λMm

answer is B.

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Detailed Solution

λ=h2meV (for electron)

λ'=h2MeV  (for proton) ⇒λ'=λmM

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