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An electron of mass $m_{e}$ and a proton of mass $m_{p} = 1836 m_{e}$ , are moving with the same speed. The ratio of their de Broglie wavelength $\frac{λ_{e l e c t r o n}}{λ_{p r o t o n}}$ will be:

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1836

$\frac{1}{1836}$

918

answer is A.

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Detailed Solution

$\Rightarrow \begin{array}{l} λ = \frac{h}{p} = \frac{h}{m v} \\ λ \propto \frac{1}{m} \\ R a t i o = \frac{λ_{e l e c t r o n}}{λ_{p r o t o n}} = \frac{m_{p r o t o n}}{m_{e l e c t r o n}} = \frac{1836}{1} \end{array}$

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