An electron projected with velocity v→=v0i^ in the electric field E→=E0j^ . Trace the path followed by the electron E0.

Given data: Velocity of projection of electron = v, Electric field = E Concept Used: Velocity = Vo in the x direction and E = Eo in y direction Detailed Solution:The acceleration of the electron will be -eEmj^This is constant acceleration.This motion is same as the the mass projected horizontally with velocity Vo of gravity acting vertically and we know the motion of such mass is parabola.

An electron projected with velocity v→=v0i^ in the electric field E→=E0j^ . Trace the path followed by the electron E0.

Given data: Velocity of projection of electron = v, Electric field = E Concept Used: Velocity = Vo in the x direction and E = Eo in y direction Detailed Solution:The acceleration of the electron will be -eEmj^This is constant acceleration.This motion is same as the the mass projected horizontally with velocity Vo of gravity acting vertically and we know the motion of such mass is parabola.

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An electron projected with velocity $\vec{v} = v_{0} \hat{i}$ in the electric field $\vec{E} = E_{0} \hat{j}$ . Trace the path followed by the electron E₀.

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circle

parabola

straight line in –y direction

straight line in +y direction

answer is A.

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Detailed Solution

Given data: Velocity of projection of electron = v, Electric field = E

Concept Used: Velocity = Vo in the x direction and E = E_o in y direction

Detailed Solution:

The acceleration of the electron will be $\frac{- e E}{m} \hat{j}$

This is constant acceleration.

This motion is same as the the mass projected horizontally with velocity V_o of gravity acting vertically and we know the motion of such mass is parabola.

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