An electron with kinetic energy K1 enters between parallel plates of a capacitor at an angle 'α' with the plates. It leaves the plates at angle 'β' with kinetic energy K2 . Then the ratio of kinetic energies K1:K2 will be :

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

An electron with kinetic energy K₁ enters between parallel plates of a capacitor at an angle $' α'$ with the plates. It leaves the plates at angle $' β'$ with kinetic energy K₂ . Then the ratio of kinetic energies $K_{1} : K_{2}$ will be :

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{\cos β}{\sin α}$

$\frac{\cos β}{\cos α}$

$\frac{\cos^{2} β}{\cos^{2} α}$

$\frac{\sin^{2} β}{\cos^{2} α}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

From figure, $v_{1} \cos α = v_{2} \cos β$
Question Image
$∴ \frac{K_{1}}{K_{2}} = \frac{\frac{1}{2} m v_{1}^{2}}{\frac{1}{2} m v_{2}^{2}} = \frac{v_{1}^{2}}{v_{2}^{2}} = \frac{\cos^{2} β}{\cos^{2} α}$