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Q.

An element “A” has face-centered cubic structure with edge length equal to 361 pm. The apparent radius of atom “A” is:

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a

180.5 pm

b

160.5 pm

c

127.6 pm

d

64 pm

answer is A.

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Detailed Solution

For FCC:

$a \sqrt{2} = 4 r$

Radius is calculated as:

$r = \frac{\sqrt{2} a}{4}$

$r = \frac{1 .414 \times 361}{4} r = 127 .6 pm$

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