An element A which is a part of common salt and kept under kerosene reacts with another element B, which has 17 protons in the nucleus, to give a product C. When an aqueous solution of product C is electrolyzed then compound D is formed by liberating two gases.
i) A is chlorine and B is sodium
ii) C is sodium chloride and D is sodium hydroxide
iii) A is sodium and B is chlorine
iv) C is sodium hydroxide and D is sodium chloride
v) Sodium is extracted by electrolytic reduction of fused salts

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i,ii,iii are correct

i,ii and v are correct

ii,iii and v are correct

i,iv are correct

answer is C.

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Detailed Solution

$2 N a C l \to 2 N a^{+} + 2 C l^{-}$

A = Sodium, B = Chlorine

Electrolysis of NaCl to produce NaOH and $C l_{2}$ formed.

Cathode: $2 N a^{+} + 2 H_{2} O \to 2 N a O H + H_{2}$

Anode: $2 C l^{-} \to C l_{2} + 2 e^{_}$

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