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An element crystalizes in BCC structure has atomic mass 50. Its edge length is 290PM. Calculate density of unit cell.

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$7.9 g / c m^{3}$

$8.5 g / c m^{3}$

$9.4 g / c m^{3}$

$6.81 g / c m^{3}$

answer is A.

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Detailed Solution

$d = \frac{Z \times M}{a^{3} \times N_{0}}, d = \frac{2 \times 50 g m o l e^{- 1}}{{(290 \times 10^{- 10} c m)}^{3} \times 6 \times 10^{23} M o l e^{- 1}}$

$d = 6.81 g / c m^{3}$

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