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Q.

An element crystallises in a face centred cubic (fee) unit cell with edge length ‘a’.  The distance between the centres of the two nearest octahedral voids in the crystal lattices is.

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a

2a

b

a

c

a2

d

a2

answer is A.

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Detailed Solution

The distance between two nearest octahedral voids in FCC lattice is the distance between edge centre and the body centre.
∴ Distan⁡ce=a22+a22=a24+a24=a2

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