An element crystallizes in a structure having fcc unit cell of an edge 200 pm. Calculate the density, if 100 g of this element contains 12 ×10²³ atoms.

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41.66 g/cm³

20 g/cm³

10.25 g/cm³

1.025 g/cm³

answer is A.

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Detailed Solution

$n = \frac{100}{M} = \frac{12 \times 10^{23}}{6 \times 10^{23}} = \frac{100}{M} \Rightarrow M = 50 ρ = \frac{4 \times 50}{6 \times 10^{23} \times {(200 \times 10^{- 10})}^{3}} = 41.66 g / {cm}^{3}$

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