An element has a cubic structure with a cell edge of 288 pm. The density of the element is $7.2 g {cm}^{- 2}$ . 208 g of the element has $24.16 \times 10^{23}$ number of atoms. The unit cell of this cubic structure is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

primitive

body - centred

face - centred

hexagonal

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$a = 288 pm = 288 \times 10^{- 12} m = 2.88 \times 10^{- 8} cm$

$ρ = \frac{M \times Z}{a^{3} \times N_{0}} Z = \frac{7.2 g {cm}^{- 3} \times 24.16 \times 10^{23} \times {(2.88 \times 10^{- 8} cm)}^{3}}{208} = 1.99 \approx 2$

The unit cell is body centred.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!