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An element has electronic configuration 1s² 2s² 2p⁶ 3s² 3p³. Predict their period, group and block

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Period = 3^rd, block = p, group = 15

Period = 5^th, block = s, group = 1

Period = 3^rd, block = p, group = 10

Period = 4^th, block = d, group = 12

answer is A.

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Detailed Solution

By observing principal quantum number (n), Orbital (s, p, d, f) and equating no.of $e^{-}$ ’s we are able to find the period, block and group of element in periodic table

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