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$An element having an atomic radius of 0.14 nm crystallizes in an f c c unit cell. What is the length of a side of the cell?$

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0.4 nm

0.96 nm

0.56 nm

0.24 nm

answer is D.

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Detailed Solution

$For a fcc unit cell r = \frac{\sqrt{2} a}{4} a = \frac{4 r}{\sqrt{2}} = 2 \sqrt{2} \times 0 .14 = 0 .39 \approx 0 .4 nm .$

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