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An element is found in nature in two isotopic forms with mass numbers $(A - 1)$ and $(A + 3)$ . If the average atomic mass of the element is found to be A, then the relative abundance of the heavier isotope in the nature will be

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75%

25%

66.6%

50%

answer is C.

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Detailed Solution

Let relative abundance of heavier isotope be X %

$A = \frac{(100 - X) (A - 1) + X (A + 3)}{100}$

$100 A = 100 A - x A - 100 + x + 3 x + x A$

$4 x = 100$

$∴ x = 25 .$

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