An element $Δ l = 0.01 \vec{i}$ is placed at the origin and carries a current 10A. The magnetic field on the y-axis at a distance of 0.5m from the current element is

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400nT along +Z axis

400nT along -Z axis

40nT along +Z axis

40nT along -Z axis

answer is A.

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Detailed Solution

$\vec{d B} = \frac{μ_{0}}{4 π} I (\frac{\bar{d} l \times \bar{r}}{r^{3}})$
$= 10^{- 7} \times \frac{10 (10^{- 2} \hat{i} \times 0.5 \hat{j})}{125 \times 10^{- 3}} = (40 n T) \hat{k}$

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