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An element with electronic arrangement as 2, 8, 18, 1 will exhibit the following oxidation states

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a
+ 2 & + 4
b
+ 1 & + 2
c
+ 2 only
d
+ 1 only

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detailed solution

Correct option is B

Electronic configuration 2,8,18,1 is 1s22s22p63s23p63d104s1

Therefore by loosing 1 electron it can attain stable configuration i.e. completely filled orbitals. So only +1 oxidation state will be exhibited.

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