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Q.

An element with electronic arrangement as 2, 8, 18, 1 will exhibit the following oxidation states

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a

+ 2 & + 4

b

+ 1 & + 2

c

+ 2 only

d

+ 1 only

answer is B.

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Detailed Solution

Electronic configuration 2,8,18,1 is 1s22s22p63s23p63d104s1

Therefore by loosing 1 electron it can attain stable configuration i.e. completely filled orbitals. So only +1 oxidation state will be exhibited.

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