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Q.

An element X (atomic weight = 24 gm/mol) forms a face centered cubic lattice. If the edge length of the lattice is 4 × 10^–8 cm and the observed density is 2.40 × 10³ kg/m³, then the percentage occupancy of lattice points by element X is: (Use N_A = 6 × 10²³):

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a

96

b

99.9

c

none of these

d

98

answer is A.

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Detailed Solution

Density $= Z.M / N_{A} \cdot a^{3} = 2.5 \times 10^{3} kg / m^{3}$
% occupancy = obs’d’/ Ideal ’d’x100 = 96%

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An element X (atomic weight = 24 gm/mol) forms a face centered cubic lattice. If the edge length of the lattice is 4 × 10–8 cm and the observed density is 2.40 × 103 kg/m3, then the percentage occupancy of lattice points by element X is: (Use NA = 6 × 1023):