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Q.

An element ‘X’ forms two oxides formula of 1st oxide is $X O_{2}$ . The first oxide contain 50% of oxygen. If the second oxide contains 60% oxygen. The formula of second oxide is

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a

$X O_{3}$

b

$X_{2} O_{2}$

c

$X_{2} O$

d

$X_{2} O_{3}$

answer is A.

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Detailed Solution

$\begin{array}{l} X O \\ 50 50 \\ moles = \frac{50}{x}, \frac{50}{16} = 1 : 2 \Rightarrow x = 32 \end{array}$

$moles = \frac{40}{32}, \frac{60}{16} = 1 : 3$

second oxide= $X O_{3}$

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