An element X forms two oxides. Formula of the first oxide is ${XO}_{2}$ . The first oxide contains 50% of oxygen. If the second oxide contains 60% of oxygen, the formula of the second oxide is

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$X_{2} O$

$X_{2} O_{3}$

$X_{3} O_{2}$

${XO}_{3}$

answer is A.

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Detailed Solution

I – oxide = ${XO}_{2} (\begin{array}{l} Given \\ 50 % O \\ = 50 % X \end{array})$

$\Rightarrow$ At wt of X = 32

II- Oxide : X : O

Wt : 0.4 : 0.6

2 : 3

More ratio = $\frac{2}{32} : \frac{3}{16}$

$\frac{1}{16} : \frac{3}{16}$ = 1 : 3

MF = XO₃

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