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Q.

An element $Δℓ = Δx \hat{i}$ is placed at the origin and carries a large current I = 10 A.The magnetic field on the y-axis at a distance of 0.5m. $∆$ x = 1 cm

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a

4 x 10^-8 T

b

3 x 10^-8 T

c

5 x 10^-8 T

d

4 x 10^-6 T

answer is A.

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Detailed Solution

$\begin{array}{l} | dB | = \frac{μ_{0}}{4 π} \frac{Idlsin θ}{r^{2}} \\ dℓ = Δx = 10^{- 2} m; I = 10 A; r = 0.5 m \\ θ = 90^{\circ}; \sin θ = 1 \\ | dB | = \frac{10^{- 7} \times 10 \times 10^{- 2}}{{(0.5)}^{2}} = 4 \times 10^{- 8} T \end{array}$

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