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Q.

An elevator can carry a maximum load of 1800kg(elevator+passengers) is moving up with a constant speed of 2m/s. The frictional force opposing the motion is 400N. Determine the minimum power delivered by the motor to the elevator( in horse power).

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a

8

b

22

c

20

d

59

answer is A.

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Detailed Solution

F = mg+frictional force ;  P=F→.v→

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