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An elevator of mass $4000 k g$ is moving upwards and the tension in the supporting cable is $40, 000 N$ . How far does it rise in a time of $20 s$ starting from rest?

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10 m

40 m

$20 m$

$30 s$

answer is D.

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Detailed Solution

$T = m (g + a)$

$40000 = 4000 (g + a)$

$a = 0.2$

$s = \frac{1}{2} a t^{2}$

$= \frac{1}{2} \times 0.2 \times {(20)}^{2} = 40 m$

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