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Q.

An elevator platform is going up at a speed  20ms1  and during its upward motion a small ball of 50g mas falling is downward direction strikes the platform elastically at a speed  5ms1. Find the speed (in  ms1)  with which the ball rebounds.
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answer is 45.

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Detailed Solution

The situation is analyzed in the figure we consider mass of platform to be very large comparted to that of ball, so we have
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 v1=u1e=(v2v1u2u1)=(v2u1u1(u2))
 v2=2u1=u2
Thus rebound velocity of ball is
 v2=2×20(5)=45ms1 upward

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