An elevator starts from rest with a constant upward acceleration. It moves 2 m in the first 0.6 second. A passenger in the elevator is holding a 3 kg package by a vertical string. When the elevator is moving, what is the tension in the string?

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29.4 N

62.7 N

20.6 N

4 N

answer is B.

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Detailed Solution

$Acceleration of elevator = \frac{2 s}{t^{2}} = \frac{2 (2)}{(0 .6)^{2}} = 11 .11 m / s^{2}$
Tension is string T - m (g + a) = 3 (9.8 + 11.11)= 62.73N

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