Q.

An ellipse E:x2a2+y2b2=1 passes through the vertices of the hyperbola H : x249y264=1. Let the major and minor axes of the ellipse E coincide with the transverse and conjugate axes of the hyperbola H, respectively. Let the product of the eccentricities of E and H be 12. If k is the length of the latus rectum of the ellipse E, then the value of 113k is equal to _______.

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answer is 1552.

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Detailed Solution

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Hyp:y264x249=1

An ellipse E:x2a2+y2b2=1 passes through the vertices of the hyperbola H:x249y264=1

So b2 = 64

eH=1+a2b2=1+4964 Ellipse x2a2+y2b2=1eE=1a2b2=1a264b=8,1a264×1138=1264a2×113=3264a2=322113a2=64322113l=2a2b=2864322113=1552113113l=1552

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