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Q.

An emf induced in a secondary coil is 20000V when the current breaks in the primary. The mutual inductance is 5H and the current reaches to zero in 10–4S in primary. Calculate the maximum current in the primary before the break.

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a

1A

b

0.4A

c

0.3A

d

0.2A

answer is D.

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Detailed Solution

Es=Mdipdt;

2×104=5×i10−4;i=0.4A

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