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An emf of $25.0 m V$ is induced in a 500- turn coil when the current is changing at the rate of $10.0 A / s$ . What is the magnetic flux through each turn of the coil at an instant when the current is $4.00 A$ ?

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$10 μ T . m^{2}$

$30 μ T . m^{2}$

$15 μ T . m^{2}$

$20 μ T . m^{2}$

answer is A.

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Detailed Solution

From $| ε | = L (\frac{Δ i}{Δ t}),$ we have
From $L = \frac{N Φ_{B}}{i}$

we have
$Φ_{B} = \frac{L i}{N} = \frac{(2.50 \times 10^{- 3} H) (4.00 A)}{500}$

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