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An endothermic reaction is nonspontaneous at freezing point of water and becomes feasible at its boiling point, then:

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$ΔH = - ve, ΔS = + ve$

$Both ΔH and ΔS are + ve$

$Both ΔH and ΔS are -ve$

$ΔH = + ve, ΔS = - ve$

answer is B.

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Detailed Solution

$ΔG = ΔH - TΔS At low T, ∆ H and ∆ S are positive but ∆ G is also positive at high temperature T ∆ S > ∆ H and ∆ G = - νe$

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