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An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons form a neutral helium atom is

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38.2

51.8

49.2

79.0

answer is D.

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Detailed Solution

$He \to {He}^{+} I . E_{1} = 24.6 eV$ ${He}^{+ 2} \to {He}^{+ 2} I . E_{2} = ?$

${(IE)}_{H like} \frac{{(I . E)}_{H}}{n^{2}} Z^{2}$

${(IE)}_{He}^{+} = \frac{13.6}{1^{2}} (2^{2})$

${IE}_{2} = 54.4 eV$

\ Energy required to remove both the

electrons = 24.6 + 54.4 = 79eV .

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