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Q.

An engine develops 10 kW of power. How much time will it take to lift a mass of 200 kg to a height of 40 m. $(g = 10 m / \sec^{2})$

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a

4 sec

b

5 sec

c

10 sec

d

8 sec

answer is C.

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Detailed Solution

$P = \frac{mgh}{t} = 10 \times 10^{3} \Rightarrow t = \frac{200 \times 40 \times 10}{10 \times 10^{3}} = 8 \sec$

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