Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Q.

An engine is attached to a wagon through a shock absorber of length 1.5m. The system with a total mass of 40,000 kg is moving with a speed of $72 {kmh}^{- 1}$ when the breaks are applied to bring it to rest. In the process of the system being brought to rest, the spring of the shock absorber gets compressed by 1.0m. If 90% of energy of the wagon is lost due to friction, spring constant is _____ $× 105 N / m$

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 16.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

Given, Mass of engine-wagon system, m=40,000kg

Velocity, $V = 72 × 5 / 18 = 20 m / s$

$K . E = 12 m v 2 = 12 × (40, 000) × (20) 2 = 8000000 J$

As 90%K.E of the system lost in friction, only 10% is transferred to spring. $∴ \frac{1}{2} K x^{2} = \frac{10}{100} \times 8000000$

$\Rightarrow \frac{1}{2} \times K \times 1 \times 1 = 800000$
$\Rightarrow K = 16 \times 10^{5} N / m$

Watch 3-min video & get full concept clarity

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!

An engine is attached to a wagon through a shock absorber of length 1.5m. The system with a total mass of 40,000 kg is moving with a speed of 72 kmh−1 when the breaks are applied to bring it to rest. In the process of the system being brought to rest, the spring of the shock absorber gets compressed by 1.0m. If 90% of energy of the wagon is lost due to friction, spring constant is _____ × 10 5 N/m