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Q.

An engine operates by taking a monatomic ideal gas through the cycle shown in the figure. The percentage efficiency of the engine is close is ______.

(Round off to nearest integer)

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answer is 19.

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Detailed Solution

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From the figure,

Work, W = 2P0V0

Heat given, Qin = WAB + WBC = n . CV ΔTAB + nCPΔTBC

= n 3R2(TB-TA)+n5R2(TC-TB)

(   CV=3R2and  CP=5R2)

=32(PBVB-PAVA) + 52(PCVC-PBVB)

=32×[3P0V0-P0V0] + 52(6P0V0-3P0V0)

= 3P0V0+152P0V0=212P0V0

Efficiencyη  = WQin=2P0V0212P0V0=421η%=4002119

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