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An engine pumps water continuously through a hose Water leaves the hose with a velocity 'v' and 'm' mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water

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$\frac{1}{2} m^{2} v^{2}$

$\frac{1}{2} m v^{3}$

$m v^{3}$

$\frac{1}{2} m v^{2}$

answer is B.

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Detailed Solution

Length of water jet leaving the hose in unit time = v

Man of water leaving the hose in unit time = mv.
Kinetic energy leaving the hose per unit time

$\frac{1}{2} (m v) v^{2}$

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