An engine take in compressed steam at $127^{0} C$ and rejects it at $47^{0} C .$ Efficiency of the engine is

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$60 %$

$20 %$

$40 %$

$35 %$

answer is C.

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Detailed Solution

$T_{1} = 127 + 273 = 400 K$
$T_{2} = 47 + 273 = 320 K$
$η = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{320}{400} \Rightarrow η = \frac{400 - 320}{400}$
$\Rightarrow η = \frac{80}{400} = \frac{1}{5} \Rightarrow η = \frac{1}{5} \times 100 = 20 %$

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